Help With Angel Eyes
Thanks man, as I am no expert on this issue I made a drawing to see if I got it right

Is that correct this way? The resistor goes on the negative wire? What if I use like a 560 Ohms, wouldn´t that be better?
Thanx

Is that correct this way? The resistor goes on the negative wire? What if I use like a 560 Ohms, wouldn´t that be better?
Thanx
Moderator


Joined: Feb 2009
Posts: 11,732
Likes: 5
From: Leesville, Louisiana
Vehicle: 2001 Hyundai Tiburon
no man... like this.

You can lengthen the wire and put the LED in your grill or something.... maybe illegal in your state.
To make them cover a larger area, file down the tip until it's completely flat, not rounded at all.

You can lengthen the wire and put the LED in your grill or something.... maybe illegal in your state.
To make them cover a larger area, file down the tip until it's completely flat, not rounded at all.
Great, thanks a lot DrivingTiburonNaked and Tibby01, now I got it. I´ll pop my headlights open for the fifth time on sunday (these damn things now open up almost by theirselfs) smile.gif and will do that, hope it´s the last time for a long, long time.
Thanx buddies
Sorry to bother again, I fount this resistor calculator on http://led.linear1.org/led.wiz and if you look at the drawing:
Solution 0: 2 x 1 array uses 2 LEDs exactly





The wizard says: In solution 0:
* each 470 ohm resistor dissipates 188 mW
* the wizard says the color code for 470 is yellow violet brown
* the wizard thinks 1/2W resistors are needed for your application Help
* together, all resistors dissipate 188 mW
* together, the diodes dissipate 128 mW
* total power dissipated by the array is 316 mW
* the array draws current of 20 mA from the source.
you can see that they recommend to put the resistor at the end on the negative wire, now I am confused again. And I should use a 1/2W resistor not the 1/4W. I am really sorry for all this questioning but I am just tired of doing things wrong and opening my headlights, I want it done and get over with it.
Thanx
Thanx buddies
Sorry to bother again, I fount this resistor calculator on http://led.linear1.org/led.wiz and if you look at the drawing:
Solution 0: 2 x 1 array uses 2 LEDs exactly





The wizard says: In solution 0:
* each 470 ohm resistor dissipates 188 mW
* the wizard says the color code for 470 is yellow violet brown
* the wizard thinks 1/2W resistors are needed for your application Help
* together, all resistors dissipate 188 mW
* together, the diodes dissipate 128 mW
* total power dissipated by the array is 316 mW
* the array draws current of 20 mA from the source.
you can see that they recommend to put the resistor at the end on the negative wire, now I am confused again. And I should use a 1/2W resistor not the 1/4W. I am really sorry for all this questioning but I am just tired of doing things wrong and opening my headlights, I want it done and get over with it.
Thanx
Moderator


Joined: Feb 2009
Posts: 11,732
Likes: 5
From: Leesville, Louisiana
Vehicle: 2001 Hyundai Tiburon
You may want to consider using MORE resistance as it is the hottest area of the vehical people usually put LEDs. Like you could add an extra 50-100 ohms for $1 at radio shack and still have 3 resistors to spare. It's a trade, brightness for longevity. You could run 2 leds to compensate, just file them down on the sides and stick them together.


