weight reduction formula
does anyone know if theres a formula that exists, that tells you for so many pounds you shed in weight reduction, it'll equal a certain number or percentage of performance?
I wouldn't think that less weight would make more power. It's more of a power to weight ratio in regards to how much weight is having to be pulled by each HP. The reason I say you won't get more power is because if you put a car on a dyno, the weight really won't make much of a diff unless you change out your wheels/tires to lighter ones between the runs. Now, you acceleration/deceleration times will be reduced because of the lighter load on the engine so 1/4 mile times would increase. A 150hp engine in a 2000lb car will still be 150hp in a 3000lb car but the lighter car will "perform" much better due to the lower load on the engine. I hope this helps.
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Joined: Mar 2006
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From: Lacey, WA
Vehicle: Two Accents, Mini, Miata, Van, Outback, and a ZX-6
If you calculate your lbs/hp you can get a general idea.
My Accent made 100whp. It weighs about 2450lbs.
2450(lbs)/100(hp) = 24.5lbs/hp
If I strip the car and get it down to 2100lbs:
2100/100 = 21lbs/hp.
So, 24.5lbs/hp is about where I'm at, and 0lbs/hp would be infinitely fast. As I lessen the weight and/or raise the power the lbs/hp will go down and your acceleration will speed up.
My Accent made 100whp. It weighs about 2450lbs.
2450(lbs)/100(hp) = 24.5lbs/hp
If I strip the car and get it down to 2100lbs:
2100/100 = 21lbs/hp.
So, 24.5lbs/hp is about where I'm at, and 0lbs/hp would be infinitely fast. As I lessen the weight and/or raise the power the lbs/hp will go down and your acceleration will speed up.




