well, most leds use 20 milliamps. you are using a 470 ohm resistor.
by manipulating the ohm's law equation, you can get: P = (A^2)xR so, .02 squared times 470 is .188W. you will have to use the quarter watt resistor(.25). a 1/8 watt resistor would burn up. |
^^ :blink:
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Thanx Tibby!
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